A + 17 nc charge is located at the origin. what is the strength of the electric field at the position (x, y) = (5.0cm, 0cm) ? express your answer using

Question

Physics

Abel

10 March, 08:07

A + 17 nc charge is located at the origin. what is the strength of the electric field at the position (x, y) = (5.0cm, 0cm) ? express your answer using

+5

Answers (1)

Know the Answer?

Nina Mcgee · Answer 1

The working equation to be used for this is written below:

E = kQ/d²

where

E is the electric field

k is a constant equal to 8.99 x 10⁹ N m²/C²

Q is the charge

d is the distance

E = (8.99 x 10⁹ N m²/C²) (17*10⁻⁹ C) / (0.05 m) ²

E = 61,132 N/C