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28 April, 21:05

A test charge is placed at a distance of 3.5 meters from a charge of 8.7 * 10-9 coulombs. What is the electric field strength at the test charge? (k = 9.0 * 109 newton·meter2/coulomb2) 6.4 newtons/coulomb 8.7 newtons/coulomb 3.5 newtons/coulomb 9.0 newtons/coulomb Done

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  1. 28 April, 22:17
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    In order to calculate the electric field strength, we may use the formula:

    E = kQ/d²

    Where Q is the charge and d is the distance between the charge and the test charge. Substituting the values into the equation:

    E = (9 x 10⁹) (8.7 x 10⁻⁹) / (3.5²)

    E = 6.39 Newtons per coulomb

    Therefore, the answer is 6.4 Newtons/coulomb
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