A top of rotational inertia 4.0 kg m2 receives a torque of 2.4 nm from a physics professor. the angular acceleration of the body will be

Question

Physics

Sariah

14 July, 02:46

A top of rotational inertia 4.0 kg m2 receives a torque of 2.4 nm from a physics professor. the angular acceleration of the body will be

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Answers (1)

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Mya Riggs · Answer 1

Angular acceleration is simply the ratio of the Torque over the rotation inertia, that is:

Angular acceleration = Torque / Rotational inertia

So substituting the values:

Angular acceleration = 2.4 N m / 4.0 kg m2

Angular acceleration = 0.7 rad/s^2