A force of 5000 n is applied outwardly to each end of a 5.0-m long rod with a radius of 34.0 mm and a young's modulus of 125 x 108 n/m2. the elongation of the rod is:

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Physics

Terry Mccarthy

28 February, 01:24

A force of 5000 n is applied outwardly to each end of a 5.0-m long rod with a radius of 34.0 mm and a young's modulus of 125 x 108 n/m2. the elongation of the rod is:

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Armani Castaneda · Answer 1

Por definicion tenemos que

(F/A) = E (∆/0)

Sustituyendo los valores tenemos y despejando ∆:

∆ = (F / (πr2 * E)) * 0

(5000*5) / (3.14 * (34*10^-2) ^2 * (125*10^8))

5.5*10^-6 m