A ball with a horizontal speed of 1.25 m/s rolls off a bench 1.00 m above the floor. part a how long will it take the ball to hit the floor?

Working formula:

y = v*t + 0.5*a*t^2

where:

y = vertical distance = - 1 m

v = initial velocity = 1.25m/s

a = acceleration = 9.81 m/s^2

t = time

Required: t

Solution:

y = v*t + 0.5*a*t^2

1 = (1.25) * t + 0.5*9.81*t^2

0 = - 1 + 1.25t + 4.905t^2

Applying completing the square, we get

t = 0.342 s, - 0.597s

Technically, we don't have time with negative value. Thus, the answer is t = 0.342 seconds