How many electrons pass through a standard 60 watt light bulb in one second?

A standard 60 W light bulb has a voltage of 130 volts. So, we use this conversion, the Faraday's constant which is equal to approximately 96,500 Coulombs per mole electron, and the Avogadro's number equal to 6.022*10²³ particles/mole. The solution is as follows:

W = Energy/time

60 W = x J/1 s

x = 60 J = 60 C·V

(60 C·V) * (1/130 V) * (1 mole e/96,500 C) * (6.022*10²³ electrons/mole electron)

= 2.88*10¹⁸ electrons