A wood block, after being given a starting push, slides down a ramp at a constant speed. what is the angle of the ramp above horizontal? suppose that μk = 0.35.

The solution for the problem is:

Constant speed means Fnet = 0.

Let m = mass of wood block and Θ = angle of ramp; then if µk = 0.35 ...

The computation would be:

Fnet = 0 = mg (sin Θ) - (µk) (mg) (cos Θ)

mg (sin Θ) = µk (mg) (cos Θ)

µk = tan Θ

Θ = arctan (µk)

= arctan (0.35)

≈ 19.3°