How much heat is absorbed by a 125 g sample of water when it is heated from 25.20 ºc to 32.80 ºc? the specific heat of water is 4.184 j/g ºc?

We can use the equation of

E = mc△T

To calculate the total heat absorbed.

E is the total heat absorbed (energy used)

m is mass.

c is specific heat capacity and

△T is the temperature change.

E = 125 x 4.184 x (32.8 - 25.2)

E = 3974.8 J

Therofre the total heat absorbed is 3974.8 joules.