A sprinkler sprays water out of a hose with a velocity of 6.3 m/s. if the sprinkler is aimed 25Â° above the ground, at what distance from the sprinkler does the water hit the ground? ignore air resistance and use 9.8 m/s2 for acceleration due to gravity.

Question

Physics

Dillon Cobb

22 July, 17:30

A sprinkler sprays water out of a hose with a velocity of 6.3 m/s. if the sprinkler is aimed 25Â° above the ground, at what distance from the sprinkler does the water hit the ground? ignore air resistance and use 9.8 m/s2 for acceleration due to gravity.

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Dexter Mercado · Answer 1

The step by step solution would be:

1. Look for the vertical component of spray, this is calculated by: (sin 25 degrees x 6.3) = 2.662 m/sec.

2. Then look for the time to max height = (v/g) = 2.662/9.8 = 0.272 sec.

3. Double the amount you got from 2; this is for time to reach the ground, = 0.544 sec.

4. Then compute for the horizontal V of spray = (cos 25 degrees x 6.3) = 5.710 m/sec.

5. So the horizontal distance = (5.710 x 0.544) = 3.106 meters.