A particle is at the position (x, y, z) = (1.0, 2.0, 3.0) m. it is traveling with a vector velocity (-5.3, - 4.8, - 3.9) m/s. its mass is 7.6 kg. what is its vector angular momentum about the origin?

Question

Physics

Omar Miranda

1 May, 13:22

A particle is at the position (x, y, z) = (1.0, 2.0, 3.0) m. it is traveling with a vector velocity (-5.3, - 4.8, - 3.9) m/s. its mass is 7.6 kg. what is its vector angular momentum about the origin?

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Answers (1)

Know the Answer?

Clarence Randall · Answer 1

x (7.6) x stands for cross product

What does the above notation mean?

Multiply 7.6 to each component of the velocity vector to obtain the linear momentum vector. Find the cross product of the position vector and the linear momentum vector. That gives you the angular momentum vector.

7.6 * - 5.3 = - 40.28

7.6 * - 4.8 = - 36.48

7.6 * - 3.9 = - 29.64

Cross Multiplication

-40.28 1 = - 80.56 - (-36.48)

-36.48 2

-40.28 1 = - 120.84 - (-29.64)

-29.64 3

-36.48 2 = - 109.44 - (-59.28)

-29.64 3

answer is (-91.2) - (50.16) + 117.04 = - 24.32