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25 October, 13:10

A person pushes a 16.0-kg shopping cart at a constant velocity for a distance of 16.0 m. she pushes in a direction 30.0° below the horizontal. a 54.0-n frictional force opposes the motion of the cart. (a) what is the magnitude of the force that the shopper exerts? n (b) determine the work done by the pushing force. j (c) determine the work done by the frictional force. j (d) determine the work done by the gravitational force. j

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  1. 25 October, 16:39
    0
    Let:

    P - pushing force,

    t - angle below horizontal,

    F - friction force.

    Resolving horizontally:

    P cos (t) = F

    (a)

    P = F / cos (t)

    = 54 / cos (30.0)

    = 62.35

    (b)

    Work done by P

    = P cos (t) * 16.0

    = F * 16.0

    = 54.0 * 16.0

    = 864J

    (c)

    Work done by F

    = - F * 16.0

    = - 54 * 16.0

    = - 864 J.

    (d)

    As there is no motion vertically, the work done by the gravitational force is 0.
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