To practice problem-solving strategy 5.2 dynamics problems. a 30.0-kg box is being pulled across a carpeted floor by a horizontal force of 230 n, against a friction force of 210 n. what is the acceleration of the box

Refer to the diagram shown below.

The net driving force is

F = 230 - 210 = 20 N

The weight of the box is

W = (30 kg) * (9.8 m/s²) = 294 N

The normal reaction is equal to the weight, so

N = 294 N

Let a = the acceleration of the box.

According to Newton's Law of motion,

F = ma

20 N = (30 kg) * (a m/s²)

a = 2/3 m/s² or 0.667 m/s²

Answer: 0.667 m/s² (or 2/3 m/s²)