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10 February, 20:06

A speeding car traveling north at 80mph passes the tramway intersection when the police begin pursuit. The police start 6 miles south of tramway traveling at 100mph. How many miles north of tramway will they be when they catch up with the speeding car?

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  1. 10 February, 22:25
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    Refer to the diagram shown below.

    Define

    x = distance, miles, that the speeding car travels before the police catch up.

    t = time, hrs, before the police catch up.

    Then

    (80 m/h) * (t h) = (x mi)

    80t = x (1)

    (100 mi/h) * (t h) = (x+6 mi)

    100t = x + 6 (2)

    Subtract (1) from (2).

    100t - 80t = x+6 - x

    20t = 6

    t = 6/20 = 0.3 h

    From (1), obtain

    x = 80*0.3 = 24 mi.

    Answer: 24 miles
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