In a slap shot a hockey player accelerates the puck from a velocity of 9.00 m/s to 60.0 m/s in the same direction. if this takes 3.33 ✕ 10-2 s, calculate the distance over which the acceleration acts.

First, you have to calculate the value of the constant acceleration according to the equation below:

a = (v, final - v, initial) / t

Substituting the values,

a = (60 m/s - 9 m/s) / 3.33*10⁻² s

a = 1,531.53 m/s²

We use the value of a to determine the distance using the equation below:

2ad = v, final² - v, initial²

2 (1,531.53 m/s²) (d) = (60 m/s) ² - (9 m/s) ²

Solving for d,

d = 1.15 meters