Ask Question
11 October, 21:39

Shown is a top view of a 50-kg person walking on a large horizontal disk, which rotates with constant angular velocity ω0 = 0.3 rad/s. He walks at a constant speed v0 = 5 m/s along a straight line painted on the disk. What is the magnitude of the horizontal force exerted on him by the disk when he is 6 m from the center of the disk? A person is shown walking from the center of a disk.

+4
Answers (1)
  1. 11 October, 23:08
    0
    We are given

    m = 50 kg

    ω0 = 0.3 rad/s

    v0 = 5 m/s

    r = 6 m

    We are asked for the horizontal force.

    Doing a force balance:

    Fc = Fh

    m ω²r = Fh

    Substituting

    Fh = 50 kg (0.3 rad/s) (6 m)

    Fh = 90 N
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Shown is a top view of a 50-kg person walking on a large horizontal disk, which rotates with constant angular velocity ω0 = 0.3 rad/s. He ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers