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26 August, 23:41

A rightward force of 246 N is applied to a 35 N suitcase to accelerate it across the floor. The coefficient of friction between the crate and the floor is 0.75. What is the acceleration of the crate?

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  1. 27 August, 03:32
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    (35/g) = mass of 3.57kg. (9.8 for g).

    (35 x 0.75) = 26.25N. friction.

    (246 - 26.25) = net 219.76N. accelerating force.

    Aceleration = (f/m) = (219.76/3.57) = 61.56m/sec^2
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