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21 September, 04:21

Because there is very little friction, the lever is an extremely efficient simple machine. using a 90.0% efficient lever, what input work is required to lift a (n) 19.0 kg mass through a distance of 45 cm? 3232 incorrect: your answer is incorrect. seenkey 93.2 j

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  1. 21 September, 04:41
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    more simply efficiency n=output work/input work = mgh/W (in) W (in) = 18*9.81*0.5/0.90=98.1 Joule
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