Ask Question
28 March, 19:05

The specific heat of aluminum is 0.0215 cal/g°c. if a 4.55 g sample of aluminum absorbs 2.55 cal of energy, by how much will the temperature of the sample change?

+2
Answers (1)
  1. 28 March, 19:46
    0
    The formula we will use on this one is:

    E = m C ΔT

    where,

    E = energy

    m = mass of sample

    C = specific heat

    ΔT = change in temperature

    Calculating for ΔT:

    ΔT = E / m C

    ΔT = 2.55 cal / (4.55 g * 0.0215 cal/g°C)

    ΔT = 0.098 °C
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “The specific heat of aluminum is 0.0215 cal/g°c. if a 4.55 g sample of aluminum absorbs 2.55 cal of energy, by how much will the ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers