The inner and outer surfaces of a 5m x 6m brick wall of thickness 30 cm and thermal conductivity 0.69 w/m. 0 c are maintained at temperature of 20 0 c and 50 c, respectively. determine the rate of heat transfer through the wall, in w.

The working equation to be used here is written below:

Q = kA (T₁ - T₂) / Δx

where

Q is the rate of heat transfer

k is the heat transfer coefficient

A is the cross-sectional area of the wall

T₁ - T₂ is the temperature difference between the sides of the wall

Δx is the thickness of the wall

The solution is as follows:

Q = (0.69 W/m²·°C) (5 m * 6 m) (50°C - 20°C) / (30 cm * 1 m/100 cm)

Q = 2,070 W/m