A particular airplane will reach liftoff at a speed of 120 km/h. (a) what minimum constant acceleration does the airplane require for it to liftoff after a takeoff run of 270 m? (enter the magnitude only.)

The working equation for this problem is a derived equation from the rectilinear motion at constant acceleration. The equation is written below:

2ax = v² - v₀²

where

a is the acceleration

x is the distance

v is the final velocity

v₀ is the initial velocity

Of course, the plane starts from rest, so v₀ = 0. The final velocity is the liftoff speed which is v = 120 km/h. Substituting the values:

2a (270 m) = (120 km/h) ² - 0²

Solving for a,

a = 26.67 km/h²