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30 December, 13:57

A flat surface of area 3.20 m2 is rotated in a uniform electric field of magnitude e = 6.20 x 105 n/c. determine the electric flux through this area (a) when the electric field is perpendicular to the surface and (b) when the electric field is parallel to the surface.

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  1. 30 December, 17:12
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    The electric flux on a surface of area A in a uniform electric field E is given by

    φ = EA cos θ

    where θ = the angle between the directions of E and a normal vector to the surface of the area.

    See the diagram shown below.

    When the electric field is perpendicular to the surface, then θ = 0°, and

    φ = EA cos (0°) = (6.20 x 10⁵ N/C) * (3.2 m²) = 1.984 x 10⁶ (N-m²) / C

    When the electric field is parallel to the area, then θ = 90°, and

    φ = EA cos (90°) = 0

    Answer:

    (a) 1.984 x 10⁶ (N-m²) / C

    (b) 0
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