Ask Question
25 November, 00:54

A 1.60-m-long barbell has a 25.0 kg weight on its left end and a 37.0 kg weight on its right end. you may want to review (pages 204 - 205). part a if you ignore the weight of the bar itself, how far from the left end of the barbell is the center of gravity

+3
Answers (1)
  1. 25 November, 03:06
    0
    Refer to the diagram shown below.

    The weight at the left end is

    W₁ = (25.0 kg) * (9.8 m/s²) = 245 N

    The weight at the right end is

    W₂ = (37.0 kg) * (9.8 m/s²) = 362.6 N

    The reaction at the fulcrum is

    R = W₁ + W₂

    Let x = distance of the fulcrum (c. g.) from the left end.

    For equilibrium, take moments about the center of gravity (c. g).

    (245 N) * (x m) - (362.6 N) * (1.6-x m) = 0

    245x - 580.16 + 362.6x = 0

    607.6x = 580.16

    x = 0.955 m

    Answer: 0.955 m
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A 1.60-m-long barbell has a 25.0 kg weight on its left end and a 37.0 kg weight on its right end. you may want to review (pages 204 - 205). ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers