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10 January, 13:11

The board sandwiched between two other boards shown below weighs 87.5 n. if the coefficient of friction between the boards is 0.622, what must be the magnitude of the compression forces (assume horizontal) acting on both sides of the center board to keep it from slipping?

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  1. 10 January, 15:49
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    Refer to the diagram shown below.

    W = 87.5 N, the weight of the sandwiched board.

    μ = 0.622, the static coefficient of friction.

    From the free body diagram of the sandwiched board, obtain

    2μF = W

    F = W / (2μ) = 87.5 / (2*0.622) = 70.34 N

    Answer: 70.34 N
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