Omar is attempting to jump across a mud puddle. If he jumps with a velocity of two m/s eastward across the puddle and lands 1.7 seconds later on the other side of the puddle, what is the maximum width the puddle can be so that he crosses safely?

A. 1.2 meters wide

B. 3.4 meters wide

C. 3.7 meters wide

D. 4.2 meters wide

Question

Physics

Jordyn

5 June, 06:10

Omar is attempting to jump across a mud puddle. If he jumps with a velocity of two m/s eastward across the puddle and lands 1.7 seconds later on the other side of the puddle, what is the maximum width the puddle can be so that he crosses safely?

A. 1.2 meters wide

B. 3.4 meters wide

C. 3.7 meters wide

D. 4.2 meters wide

+5

Answers (1)

Know the Answer?

Edward · Answer 1

Horizontal distance can be computed using the formula:

dx = vt

Where:

dx=horizontal distance

v=velocity

t = time

Your problem gives you the velocity and time; 2 m/s and 1.7s respectively. All you need to do is fill in what you know and solve for what you don't know.

dx=vt

dx = (2m/s) (1.7s)

dx=3.4m

The answer is then B.