Use these relationships to determine the number of calories to change 1.5 kg of 0∘c ice water to 1.5 kg of 100∘c boiling water.

The latent heat of fusion of water is 80 cal/g.

The specific heat of water is 1 cal/g-C.

The latent heat of vaporization of water is 540 cal/g.

Therefore, if we have 1.5 kg = 1500 g, the total heat requirement is:

1500 g[ (80 cal/g) + (1 cal/g-C) (100 - 0) C + (540 cal/g) ] = 1500 g (720 cal/g) = 1,080,000 cal.