Calculate the orbital period of a spacecraft in an orbit 300 kilometers above earth's surface

The formula that will be used to solve this question is:

P = 2π sqrt[ a^3 / (GM) ] where:

GM = 3.986004418 x 10^-14 m^3 sec^-2

a = 6378000 + 300000 = 6678000 meters

Substitute in the equation to get the period as follows:

P = 2π sqrt [ (6678000) ^3 / (3.986004418 x 10^-14) ]

P = 5431.0 seconds