A flashlight operates on a 9.00 v battery and has a resistance of 45. At what rate does the flashlight use electric energy

What is required is calculation of power. Power is the rate of use of energy in J/s (W).

P = VI, but V = IR = > I = V/R

Then,

P = V^2/R

Where

P = Power in J/s or W

V = Voltage, in volts

R = Resistance in ohms

Substituting;

P = 9^2/45 = 1.8 W