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20 April, 10:59

A car slows down uniformly from a speed of 29.0 m/s to rest in 8.20 s how far did it travel

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  1. 20 April, 12:36
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    For this problem, we use the derived equations for rectilinear motion at constant acceleration.

    a = (v - v₀) / t

    x = v₀t + 0.5t²

    where

    a is acceleration

    v₀ and v are the initial and final velocities, respectively

    x is the distance

    t is the time

    The solution is as follows:

    a = (29 m/s - 0 m/s) / 8.20 s = 3.54 m/s²

    Using this to the second equation:

    x = (0 m/s) (8.20 s) + 0.5 (3.54 m/s²) (8.20 s) ²

    x = 119 m
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