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7 October, 01:14

A ball whose mass is 0.3 kg hits the floor with a speed of 7 m/s and rebounds upward with a speed of 4 m/s. if the ball was in contact with the floor for 1.5 ms (1.5multiply10-3 s), what was the average magnitude of the force exerted on the ball by the floor? favg = 602.94 incorrect: your answer is incorrect. n.

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  1. 7 October, 04:13
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    Newton's second law is stated as:

    F=ma,

    a = (7-4) / 1.5 = 2 m/s^2 (it is a deceleration due to impact with floor. And thus the ball exerts force on the floor).

    Therefore,

    F = 0.3*2 = 0.6 N
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