A tiger travels 3m/s^2 for 4.1s, what was its initial speed if it's final speed was 55k/h?

Acceleration a=3m/s^2

time t = 4.1seconds

Final velocity V = 55km/h

initial velocity U = ?

First convert V to m/s

36km/h=10m/s

55km/h = 55*10/36=15.28m/s

Using the formula V = U+at

U = V-at

U = 15.28-3*4.1=15.28-12.3=2.98m/s

Initial velocity U = 2.98m/s or 10.73km/h (Using the conversion rate 36km/h=10m/s)