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26 February, 03:21

The springs of a 1000 kg car compress 5.5 mm when its 68 kg driver gets into the driver's seat. If the car goes over a bump, what will be the frequency of vibrations?

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  1. 26 February, 06:53
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    1. Find the spring constant k:

    F = mg = kx

    68 * g = k * 0.0055m

    k = 121287.273

    2. Find the frequency f:

    ω = 2πf = √k/m

    f = √ (k / m) / 2π = 1.7
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