A car traveling at a speed of v can brake to an emergency stop in a distance x. assuming all other driving conditions are all similar, if the traveling speed of the car doubles, the stopping distance will be

We will use the formula:

2as = v² - u²; where the final velocity v is 0, the distance s will be represented by x and the initial velocity will be represented by v. So:

2ax = - v²

x ₁ = 1/2 av²

for the distance it takes to stop, let's see what happens when we double the value v

x ₂ = 1/2 A (2v) ² = 4 (1/2 * av²)

Now divide the formulae, getting

x ₂ / x₁ =

(4 (1/2 * av²)) / (1/2 av²) = 4

Doing the division, everything cancels out except for the value 4. So if your speed doubles, the stopping distance quadruples, or becomes 4 times the original.