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21 July, 14:18

The radius of a niobium atom is 131 pm. how many niobium atoms would have to be laid side by side to span a distance of 2.40 mm

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  1. 21 July, 17:48
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    First, we must know the following conversions:

    1 pm = 10⁻¹² m

    1 mm = 10⁻³ m

    Therefore,

    1 pm = 10⁻⁹ mm

    The radius of the atom is 131 pm, which means that the span of one atom, the diameter, is 262 pm.

    Number of atoms needed = distance to be covered / span of one atom

    Number of atoms needed = 2.4 / 262 x 10⁻⁹

    Number of atoms needed = 9.16 x 10⁷

    9.16 x 10⁷ atoms of niobium will be needed
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