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17 November, 12:56

A 12 oz can of soda is left in a car on a hot day. In the morning the soda temperature was 60oF with a gauge pressure of 40 psi. What will the gauge pressure be when the soda reaches 90oF (or 363 Kelvin) ?

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  1. 17 November, 15:07
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    Using the Gay Lussac's Pressure Temperature Law:

    P1/T1 = P2/T2

    Substituting the values:

    Let x be the new gauge pressure.

    40/60 = x/90

    x = 60 psi.

    T he gauge pressure will be 60 psi when the soda reaches 90oF.
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