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11 October, 16:09

It takes 3.3 j of work to stretch a hooke's-law spring 15 cm from its unstressed length. how much the extra work is required to stretch it an additional 11.3 cm? answer in units of j.

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  1. 11 October, 18:54
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    5.786j

    Set up a proportion. Add 11.3 and 15=26.3cm.

    Next, the proportion of 3.3j/15cm=*/26.3cm
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