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13 January, 18:00

What is the acceleration of the car when vx = 16.9 m/s?

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  1. 13 January, 18:09
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    There is no Vx (t). So let us assume it is = (0.910 m/s^3) t^2.

    Since a = dv/dt,

    a (t) = 0.91*2t = 1.82t

    To look for the t at which v = 16.9 m/s

    16.9 = 0.91*t^2

    t = sqrt (16.9/0.91) = 4.31 s

    a (4.31) = 1.82*4.31

    =~7.84 [m/s^2] would be the answer.
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