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28 September, 18:59

Problem 2.26 MasteringPhysics 10 of 16 Problem 2.26 When striking, the pike, a predatory fish, can accelerate from rest to a speed of 3.9 m/s in 0.11 s Part B How far does the pike move during this strike?.

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  1. 28 September, 20:32
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    final velocity = initial velocity + (acceleration x time)

    3.9 m/s = 0 m/s + (acceleration x 0.11 s)

    3.9 m/s / 0.11 s = acceleration

    30.45 m/s^2 = acceleration

    distance = (initial velocity x time) + 1/2 (acceleration) (time^2)

    distance (0 m/s x 0.11 s) + 1/2 (30.45 m/s^2) (0.11s ^2)

    distance = 0.18 m
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