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17 November, 19:23

What is the average kinetic energy in joules of hydrogen atoms on the 5500ºc surface of the sun?

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  1. 17 November, 23:06
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    The kinetic energy is related to the temperature of the system using this formula:

    E = (3/2) kT

    where

    k is the Boltzmann's constant (1.38*10⁻²³ J/K)

    The temperature in K is:

    T = 5500 + 273 = 5773 K

    E = (3/2) (1.38*10⁻²³ J/K) (5773 K)

    E = 1.195*10⁻¹⁹ J
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