Our boss asks you compare two sound waves and determine which has the higher frequency. Wave A has a period of 4⁄100 second and Wave B has a perio of 1⁄7 second.

Wave A - period = 4/100 and the frequency = 1 / (4/100) = 100/4 = 25 Hz

Wave B - period = 1/7 and the frequency = 1 / (1/7) = 7 Hz

Wave A has a higher frequency.

The periodic time is the inverse of frequency. This means that:

Period = 1/frequency

Therefore,

Frequency = 1/period

For wave A:

period = 4/100

frequency = 1 / (4/100) = 100/4 = 25 Hz

For wave B:

period = 1/7

frequency = 1 / (1/7) = 7 Hz

Based on this, wave A has higher frequency.