How much heat is released when a 10.0-g sample of iron cools from 75.0°c to 25.5 °c? the specific heat capacity of iron is 0.449 j/g · °c?

M = 10.0 g, the mass of the iron sample

ΔT = 75 - 25.2 = 49.5°C, the decrease in temperature

c = 0.449 J / (g-°C), the specific heat of iron

The heat released is

Q = m*c*ΔT

= (10.0 g) * (0.449 J / (g-°C)) * (49.5 C)

= 222.255 J

Answer: 222.3 J (nearest tenth)