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28 July, 04:46

How much heat is released when a 10.0-g sample of iron cools from 75.0°c to 25.5 °c? the specific heat capacity of iron is 0.449 j/g · °c?

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  1. 28 July, 07:25
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    M = 10.0 g, the mass of the iron sample

    ΔT = 75 - 25.2 = 49.5°C, the decrease in temperature

    c = 0.449 J / (g-°C), the specific heat of iron

    The heat released is

    Q = m*c*ΔT

    = (10.0 g) * (0.449 J / (g-°C)) * (49.5 C)

    = 222.255 J

    Answer: 222.3 J (nearest tenth)
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