The force in Newtons on a particle directed along the x-axis is given by F (x) = exp ( - (x/5) + 5) for x≥0 where x is in meters. The particle is constrained to move along the x-axis. Find the work done in Joules on the particle, W, in moving it from x=0 to x=1 using the fact that F=dW/dx. For your reference, 1 Joule = 1 Newton * 1 meter.

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Physics

Gillian Scott

13 November, 16:02

The force in Newtons on a particle directed along the x-axis is given by F (x) = exp ( - (x/5) + 5) for x≥0 where x is in meters. The particle is constrained to move along the x-axis. Find the work done in Joules on the particle, W, in moving it from x=0 to x=1 using the fact that F=dW/dx. For your reference, 1 Joule = 1 Newton * 1 meter.

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Bruce Gardner · Answer 1

From F = dW/dx u will integrate nad will have : W = Integralfrom [0 to 1] (F (x) dx) = > W = Intgral [0 ... 1] exp[ (-x/5) + 5] dx all u need is to solve this integral.