Calculate the root mean square velocity and kinetic energy of co, co2, and so3 at 312 k.

Answer: the molar gas constant "R", has the value 8.3143 J/mol K, and the temperature "T", is in Kelvin. Since the joule is the kg-m2/s2, the molar mass must be in kg/mol vrms = (the square root of) 3RT/M, vrms CO = [ (3) (255K) (8.3143 J/mol K) / (0.02801 kg/mol) ]^1/2 = 477 m/sec vrms CO2 = [ (3) (255K) (8.3143 J/mol K) / (0.04401 kg/mol) ]^1/2 = 380 m/sec vrms SO3 = [ (3) (255K) (8.3143 J/mol K) / (0.08006 kg/mol) ]^1/2 = 282 m/sec K. E. = 1/2 (mass) (velocity) 2 or = 3/2 RT Joules/mole = 1.5 (8.314 J/mol-K) (255K) = 13.78 joules per mole answer is: 13.8 J/mole is the average K. E. for any of the three gases