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27 February, 20:05

2 g of a gas initially at 4.00 atm is compressed from 8.00 l to 2.00 l at constant temperature. what is the resulting pressure in atm of the gas?

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  1. 27 February, 22:58
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    P1V1 = P2V2 - - > P2 = P1V1/V2

    P2 = 4*8/2 : 32/2 = 16atm
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