Ask Question
22 May, 19:57

A uniform, thin, solid door has height 2.20 m, width 0.870 m, and mass 23.0 kg. (a) find its moment of inertia for rotation on its hinges. (b) is any piece of data unnecessary

+2
Answers (1)
  1. 22 May, 22:34
    0
    The solution for this problem is:

    a. The moment of inertia of the thin door rotating about the hinges axis is given by:

    I = 1/3 mw^2 is to solve for the inertia, where: m is the mass and w is the width

    = 23.0 x 0.870^2 / 3

    = 17.4087 / 3

    = 5.8029 kg m^2

    b. The height of the door is not required for this calculation.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A uniform, thin, solid door has height 2.20 m, width 0.870 m, and mass 23.0 kg. (a) find its moment of inertia for rotation on its hinges. ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers