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5 December, 21:41

If 3.5 l of antifreeze solution (specific gravity = 0.80) is added to 4.0 l of water to make a 7.5-l mixture, what is the specific gravity of the mixture?

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  1. 5 December, 22:02
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    The mixture has a specific gravity of 0.91. We need to know the specific gravity of water, which is 1. We use the following equation to find the specific gravity of the mixture: Specific gravity of the mixture = (water volume * water specific gravity + antifreeze volume * antifreeze specific gravity) / volume of the mixture Specific gravity of the mixture = (4L * 1 + 3.5L * 0.80) / 7.5L Specific gravity of the mixture = 0.91
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