Ask Question
4 September, 16:47

Two satellites are in circular orbits around the earth. the orbit for satellite a is at a height of 542 km above the earth's surface, while that for satellite b is at a height of 838 km. find the orbital speed for satellite a and satellite

b.

+4
Answers (1)
  1. 4 September, 17:17
    0
    Let R be radius of Earth with the amount of 6378 km h = height of satellite above Earth m = mass of satellite v = tangential velocity of satellite

    Since gravitational force varies contrariwise with the square of the distance of separation, the value of g at altitude h will be 9.8*{[R / (R+h) ]^2} = g'

    So now gravity acceleration is g' and gravity is balanced by centripetal force mv^2 / (R+h):

    m*v^2 / (R+h) = m*g' v = sqrt[g' * (R + h) ]

    Satellite A: h = 542 km so R+h = 6738 km = 6.920 e6 m g' = 9.8 * (6378/6920) ^2 = 8.32 m/sec^2 so v = sqrt (8.32*6.920e6) = 7587.79 m/s = 7.59 km/sec

    Satellite B: h = 838 km so R+h = 7216 km = 7.216 e6 m g' = 9.8 * (6378/7216) ^2 = 8.66 m/sec^2 so v = sqrt (8.32*7.216e6) = 7748.36 m/s = 7.79 km/sec
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Two satellites are in circular orbits around the earth. the orbit for satellite a is at a height of 542 km above the earth's surface, while ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers