Ask Question
12 September, 23:48

A shopper pushes a grocery cart 20.0 m at constant speed on level ground, against a 35.0 n frictional force. he pushes in a direction 25.0? below the horizontal. what is the work done on the cart by the gravitational force?

+5
Answers (1)
  1. 13 September, 02:17
    0
    Work is calculated as the product of Force, Distance, and angular motion. In this case, the work done by gravity is perpendicular to the motion of the cart, so θ = 90°

    and W=Fdcosθ

    W=35.0 N x 20.0 m x cos90

    W=0 J

    This means that work done perpendicular to the direction of the motion is always zero.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A shopper pushes a grocery cart 20.0 m at constant speed on level ground, against a 35.0 n frictional force. he pushes in a direction 25.0? ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers