A bus is moving at 22m/s [E] for 12s. Then the bus driver slows down at 1.2m/s2 [W] until the bus stops. Determine the total displacement of the bus. (Answer is 4.7x10^2m)

The total displacement is equal to the total distance. For the east or E direction, the distance is determined using the equation:

d = vt = (22 m/s) (12 s) = 264 m

For the west or W direction, we use the equations:

a = (v - v₀) / t

d = v₀t + 0.5at²

Because the object slows down, the acceleration is negative. So,

-1.2 m/s² = (0 m/s - 22 m/s) / t

t = 18.33 seconds

d = (22 m/s) (18.33 s) + 0.5 (-1.2 m/s²) (18.33 s) ²

d = 201.67 m

Thus,

Total Displacement = 264 m + 201.67 m = 465.67 or approximately 4.7*10² m.