Calculate the amount of hcn that gives the lethal dose in a small laboratory room measuring 14 * 15 * 8.0ft. the density of air at 26∘c is 0.00118g/cm3.

Question

Physics

Jayson Francis

7 July, 22:34

Calculate the amount of hcn that gives the lethal dose in a small laboratory room measuring 14 * 15 * 8.0ft. the density of air at 26∘c is 0.00118g/cm3.

+5

Answers (1)

Know the Answer?

Cole Cowan · Answer 1

Since we are given the density and volume, then perhaps we can determine the amount in terms of the mass. All we have to do is find the volume in terms of cm³ so that it will cancel out with the cm³ in the density. The conversion is 1 ft = 30.48 cm. The solution is as follows:

V = (14 ft) (15 ft) (8 ft) (30.48 cm/1 ft) ³ = 0.0593 cm³

The mass is equal to:

Mass = (0.00118g/cm³) (0.0593 cm³)

Mass = 7 grams of HCN