A rock falls freely from rest near the surface of a planet where acceleration due to gravity is 4.0 meters per second per second. what is the speed of this rock after it falls 32 meters?

If there is a rock that is free falling from rest where acceleration due to gravity is 4.0 m/s^2, and it falls 32 meters, the velocity can be solved as follows: velocity = + - sqrt (gravity x y displacement + initial velocity^2) velocity = + - sqrt (4.0m/s^2 x 32 meters + 0^2) velocity = + - sqrt (128m/s) velocity = 11.3 m/s The speed of the rock after it falls 32 meters is 11.3m/s